在python中的while True语句之间传递信息

原文标题 ：Passing information between while True statments in python

”’我试图弄清楚如何在两个真语句之间传递信息。基本上，当玩家 1 要求一张卡片时，我想将该卡片存储在玩家 2 的记住卡片列表中。这样当轮到玩家 2 时可以检查它的手牌，如果它有，它会要求那张牌，否则； random.choice 函数会选择这张牌。接下来我想让我的玩家 2 记住它要求玩家 1 没有的牌，这样我可以防止玩家 2 在一定的回合内要求这张牌。我基本上是在尝试让我的电脑播放器变得更聪明。”’

for_player_2 = []
while True:
    if len(player_1_hand) == 0 or len(player_2_hand) == 0 or len(deck) == 0:
        break
    # Player 1's turn
    while True:
        if len(player_1_hand) == 0:
            break
        print("Your cards ", player_1_pairs)
        desired_card = input("What card would you like?\n").upper()
        # Putting this here to try to help describe what I am trying to do
        for_player_2 = []
        for_player_2 += desired_card
        if check_guess(player_2_hand, player_1_hand, desired_card, player_1_pairs)== True:
            print("Well done")
        else:
            print("Go Fish")
            player_1_had.append(deal_top_card(deck))
            drawn_card = player_1_hand[-1]
            if check_d_card(player_1_hand, player_1_pairs, desired_card, drawn_card)== Tr:
                print("Congratulations, you drew the match to your pair!!!")
                continue
            elif check_d_card(player_1_hand, player_1_pairs, desired_card, drawn_card)==F:
                for i in range(len(player_1_hand)):
                    for j in range(i + 1, len(player_1_hand):
                        # If card ranks match
                        card1 = player_1_hand[i]
                        card2 = player_1_hand[j]
                        if card1[0] == card2[0]:
                            player_1_pairs.extend([card1, card2])
                            player_1_hand.remove(card1)
                            player_1_hand.remove(card2)
                            break
            break
    #Player 2's turn
    while True:
        if len(player_2_hand) == 0:
            break
        # This is where I want to run a check to see if the card player1 just asked for is in player2's hand and if it is, player2 will ask for it, otherwise; it will run the random.choice function to pick the card.
        # Also I want to figure out how to remember when player2 asks for a card and player1 doesn't have it so I can prevent player2 from asking for it again for a certain number of turns if possible.
        player_2_choice = random.choice(player_2_hand) # I want to prevent the remembered wrong guesses for player2 from being a choice for a certain number of turns.
        if player_2_choice not in player_2_hand:
            continue
        print("Player 2 asked for ", player_2_choice)
        if check_guess(player_1_hand, player_2_hand, player_2_choice, player_2_pairs)==Tr:
            print("Player 2 got a pat on the back for guessing correctly.")
        else:
            print("Player 2 had to go fishing!!!")
            drawn_card = player_2_hand[-1]
            if check_d_card(player_2_hand, player_2_pairs, player_2_choice, d_card)==True:
                print("Player 2 got a pat on the back for drawing their pair")
            elif check_d_card(player_2_hand, player_2_pairs, player_2_choice, d_card)==F:
                for i in range(len(player_2_hand)):
                    for j in range(i + 1, len(player_2_hand):
                        # If card ranks match
                        card1 = player_2_hand[i]
                        card2 = player_2_hand[j]
                        if card1[0] == card2[0]:
                            player_2_pairs.extend([card1, card2])
                            player_2_hand.remove(card1)
                            player_2_hand.remove(card2)
                            break
            break