方法一:常规计算
#include <stdio.h>
int main(){
char c;
int letters=0,space=0,digit=0,other=0;
printf("请输入一行字符:\n");
while((c=getchar())!='\n'){
if(c>='a'&&c<='z'||c>='A'&&c<='Z')
letters++;
else if(c==' ')
space++;
else if(c>='0'&&c<='9')
digit++;
else
other++;
}
printf("字母数:%d\n空格数:%d\n数字数:%d\n其他字符数:%d",letters,space,digit,other);
return 0;
}
方法二:普通函数调用
#include <stdio.h>
#include <string.h>
void count(char c[]){
int letters=0,space=0,digit=0,other=0;
int i;
for (i = 0; c[i]; i++)
{
if(c[i]>='a'&&c[i]<='z'||c[i]>='A'&&c[i]<='Z')
letters++;
else if(c[i]==' ')
space++;
else if(c[i]>='0'&&c[i]<='9')
digit++;
else
other++;
}
printf("字母数:%d\n空格数:%d\n数字数:%d\n其他字符数:%d",letters,space,digit,other);
}
int main(){
char c[32];
printf("请输入一行字符:\n");
gets(c);
count(c);
return 0;
}
方法三:指针函数调用
#include <stdio.h>
void count(char arr[]){
int letters=0,space=0,digit=0,other=0;
char *p=arr;
char c;
while(*p!='\n') {
c =*p ;
if(c>='a'&&c<='z'||c>='A'&&c<='Z')
letters++;
else if(c==' ')
space++;
else if(c>='0'&&c<='9')
digit++;
else
other++;
p++;
}
printf("字母数:%d\n空格数:%d\n数字数:%d\n其他字符数:%d",letters,space,digit,other);
}
int main(){
char c[32];
int i =0;
printf("请输入一行字符:\n");
while((c[i]=getchar())!='\n')
i++;
count(c);
return 0;
}
文章出处登录后可见!
已经登录?立即刷新