从 3 个列表构建一个集合 – Python

社会演员多 2年前 python 243

原文标题 ：build a set from 3 lists – Python

我有以下块，我需要将“分数”定义为任何给定两个列表中每组单词的交集/联合。我明白 & 和 |只能成套使用。从studytonight我得到下面的代码应该可以工作，但它给了我> TypeError: unhashable type: ‘list’

corpus = [
    ["i","did","not","like","the","service"],
    ["the","service","was","ok"],
    ["i","was","ignored","when","i","asked","for","service"]
]
{corpus[0],corpus[1],corpus[2]}

有人可以纠正我的错误吗？

# This is my goal - but all in 1 set
set1 = {"i","did","not","like","the","service"}
set2 = {"the","service","was","ok"}
set3 = {"i","was","ignored","when","i","asked","for","service"}
set1&set3

# Even like this it gives the same error, wwhy can't I do it?
set = {
    ["i","did","not","like","the","service"],
    ["the","service","was","ok"],
    ["i","was,"ignored","when","i","asked","for","service"]


}

原文链接：https://stackoverflow.com//questions/71463110/build-a-set-from-3-lists-python

我来回复

Grismar 评论

您正在寻找：

corpus = [
    ["i","did","not","like","the","service"],
    ["the","service","was","ok"],
    ["i","was","ignored","when","i","asked","for","service"]
]

intersection = set.intersection(*map(set, corpus))

或者，从更字面的意义上说：

intersection = set(corpus[0]) & set(corpus[1]) & set(corpus[2])

2年前 0条评论

Rajat Jog 评论

你应该使用：

data = list(sum(corpus, [])) # this will convert 2d into single D list
result = set(data)

要么

results = set(list(sum(corpus, [])))

2年前 0条评论

从 3 个列表构建一个集合 – Python

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