使用未经训练的 Keras 模型预测数据

乘风 tensorflow 498

原文标题Predicting Data using an Untrained Keras Model

本质上,我想通过 Keras 模型传播数据,而无需先训练 Keras 模型。我尝试同时使用 predict() 并将原始张量输入模型。

数据是一个形状为 (3, 3) 的 2D Numpy float64 数组,完全用零填充。

该模型本身概述如下:

inputs = keras.Input(shape=(3,), batch_size=1)
FFNNlayer1 = keras.layers.Dense(100, activation='relu')(inputs)
FFNNlayer2 = keras.layers.Dense(100, activation='relu')(FFNNlayer1)
numericalOutput = keras.layers.Dense(3, activation='sigmoid')(FFNNlayer2)
categoricalOutput = keras.layers.Dense(9, activation='softmax')(FFNNlayer2)
outputs = keras.layers.concatenate([numericalOutput, categoricalOutput])
hyperparameters = keras.Model(inputs=inputs, outputs=outputs, name="hyperparameters")
hyperparameters.summary()

该模型的输出层需要两个不同的激活函数,因此我使用了函数式 API。

我第一次尝试使用hyperparameter.predict(data[0]),但不断收到以下错误:

WARNING:tensorflow:Model was constructed with shape (1, 3) for input KerasTensor(type_spec=TensorSpec(shape=(1, 3), dtype=tf.float32, name='input_15'), name='input_15', description="created by layer 'input_15'"), but it was called on an input with incompatible shape (None,).
Traceback (most recent call last):

  File "<ipython-input-144-4c4a629eaefa>", line 1, in <module>
    mainNet.hyperparameters.predict([dataset_info[0]])

  File "C:\Users\hudso\anaconda3\lib\site-packages\keras\utils\traceback_utils.py", line 67, in error_handler
    raise e.with_traceback(filtered_tb) from None

  File "C:\Users\hudso\AppData\Roaming\Python\Python38\site-packages\tensorflow\python\framework\func_graph.py", line 1129, in autograph_handler
    raise e.ag_error_metadata.to_exception(e)

ValueError: in user code:

    File "C:\Users\hudso\anaconda3\lib\site-packages\keras\engine\training.py", line 1621, in predict_function  *
        return step_function(self, iterator)
    File "C:\Users\hudso\anaconda3\lib\site-packages\keras\engine\training.py", line 1611, in step_function  **
        outputs = model.distribute_strategy.run(run_step, args=(data,))
    File "C:\Users\hudso\anaconda3\lib\site-packages\keras\engine\training.py", line 1604, in run_step  **
        outputs = model.predict_step(data)
    File "C:\Users\hudso\anaconda3\lib\site-packages\keras\engine\training.py", line 1572, in predict_step
        return self(x, training=False)
    File "C:\Users\hudso\anaconda3\lib\site-packages\keras\utils\traceback_utils.py", line 67, in error_handler
        raise e.with_traceback(filtered_tb) from None
    File "C:\Users\hudso\anaconda3\lib\site-packages\keras\engine\input_spec.py", line 227, in assert_input_compatibility
        raise ValueError(f'Input {input_index} of layer "{layer_name}" '

    ValueError: Exception encountered when calling layer "hyperparameters" (type Functional).
    
    Input 0 of layer "dense_20" is incompatible with the layer: expected min_ndim=2, found ndim=1. Full shape received: (None,)
    
    Call arguments received:
      • inputs=('tf.Tensor(shape=(None,), dtype=float32)',)
      • training=False
      • mask=None

我稍微摆弄了一下数组尺寸,但模型继续给出同样的错误。然后我尝试使用以下代码将原始张量输入模型:

tensorflow_dataset_info =  tf.data.Dataset.from_tensor_slices([dataset_info[0]]).batch(1)
aaaaa = enumerate(tensorflow_dataset_info)
predictions = mainNet.hyperparameters(aaaaa)

此代码继续给出以下错误:

Traceback (most recent call last):

  File "<ipython-input-143-df51fe8fd203>", line 1, in <module>
    hyperparameters = mainNet.hyperparameters(enumerate(tensorflow_dataset_info))

  File "C:\Users\hudso\anaconda3\lib\site-packages\keras\utils\traceback_utils.py", line 67, in error_handler
    raise e.with_traceback(filtered_tb) from None

  File "C:\Users\hudso\anaconda3\lib\site-packages\keras\engine\input_spec.py", line 196, in assert_input_compatibility
    raise TypeError(f'Inputs to a layer should be tensors. Got: {x}')

TypeError: Inputs to a layer should be tensors. Got: <enumerate object at 0x000001F60081EA40>

我在网上看了一会儿,也翻遍了 tf.data 文档,但我仍然不确定如何解决这个问题。再次,我尝试了这段代码的多种变体,我继续得到大多是相同的错误。

原文链接:https://stackoverflow.com//questions/71596616/predicting-data-using-an-untrained-keras-model

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  • LeonardoVaz的头像
    LeonardoVaz 评论

    如果data.shape = (3, 3),当你通过data[0]model.predict()时,你实际上是在发送一个形状(3, )的向量,但是你的模型期望的是形状(1, 3),这意味着 1 个大小为 3 的示例。

    尝试对数据进行切片:

    model.predict(data[:1])
    

    这样,您的张量将具有形状 (1, 3)。

    2年前 0条评论